10x+8=12x^2

Solution for 10x+8=12x^2 equation:

10x+8=12x^2

We move all terms to the left:

10x+8-(12x^2)=0

determiningTheFunctionDomain
-12x^2+10x+8=0

a = -12; b = 10; c = +8;
Δ = b2-4ac
Δ = 102-4·(-12)·8
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-22}{2*-12}=\frac{-32}{-24}
=1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+22}{2*-12}=\frac{12}{-24}
=-1/2
$